You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Electron Affinity

N 0/2 atoms ...

Question

N $_{0}$ /2 atoms of X(g) are converted into X $^{+}$ (g) by energy E $_{1}$ . N $_{0}$ /2 atoms of X(g) are converted into X $^{-}$ (g) by energy E $_{2}$ . Hence, ionisation potential and electron affinity of X(g) are:

\frac{2 E_{1}}{N_{0}}, \frac{2 (E_{1} - E_{2})}{N_{0}}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{2 E_{1}}{N_{0}}, \frac{2 E_{2}}{N_{0}}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{(E_{1} - E_{2})}{N_{0}}, \frac{2 E_{2}}{N_{0}}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

None of the above

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D $\frac{2 E_{1}}{N_{0}}, \frac{2 E_{2}}{N_{0}}$
Let, $I P = I$
$E A = E$

$X (g) \to X^{+} (g) + e^{-}$

$\frac{N_{0}}{2} I = E_{1}$

$I = \frac{2 E_{1}}{N_{0}}$

$X (g) + e^{-} \to X^{-} (g)$

$\frac{N_{o} E}{2} = E_{2}$

$E = \frac{2 E_{2}}{N_{o}}$

Suggest Corrections

Similar questions

N_o/2 atoms of X(g) are converted into X⁺(g) by energy E₁. N_o/2 atoms of X(g) are converted into X^-(g) by energy E₂. Hence the ionisation potential and electron affinity of X(g) per atom are:

A. 2E₁/N_o., 2(E₂-E₁)/N_o

B. 2E₁/N_o.,. 2E₂/N_o

C. E₁-E₂/N_{o. ,.}2E₂/N_o

D. None is correct

\frac{N_{0}}{2}

atoms of

X (g)

are converted into

X^{+} (g)

by energy

E_{1}

\frac{N_{0}}{2}

atoms of

X (g)

are converted into

X^{-} (g)

by energy

E_{2}

. Hence, ionisation potential and electron affinity of

X (g)

are:

\frac{N_{0}}{2}

atoms of

X (g)

are converted into

X^{+} (g)

by absorbing

E_{1}

energy.

2 N_{0}

atoms of

X (g)

are converted into

X^{-} (g)

by releasing

E_{2}

energy. Calculate the ionisation enthalpy and electron gain enthalpy of

X (g)

per atom.

A_{0} / 2

atoms of

X (g)

are converted into

X^{+} (g)

by absorbing energy

E_{1}

A_{0} / 2

X^{+} (g)

are converted into

X^{-} (g)

with the release of energy,

E_{2}

. Hence the ionisation energy and the electron affinity of

X (g)

are repectively _____ and _______.

No/2 atoms of $X_{(g)}$ are converted into $X_{(g)^{+}}^{+}$ by energy $E_{1}$ , No/2 atoms of $X_{g}$ are converted into $X_{(g)}^{-}$ by energy $E_{2}$ . Hence ionization potential and electron affinity of $X_{(g)}$ per atom are

Join BYJU'S Learning Program

N0/2 atoms of X(g) are converted into X+(g) by energy E1. N0/2 atoms of X(g) are converted into X−(g) by energy E2. Hence, ionisation potential and electron affinity of X(g) are:

The correct option is D 2E1N0,2E2N0Let, IP=IEA=EX(g)→X+(g)+e−N02I=E1I=2E1N0X(g)+e−→X−(g)NoE2=E2E=2E2No

N $_{0}$ /2 atoms of X(g) are converted into X $^{+}$ (g) by energy E $_{1}$ . N $_{0}$ /2 atoms of X(g) are converted into X $^{-}$ (g) by energy E $_{2}$ . Hence, ionisation potential and electron affinity of X(g) are:

The correct option is D $\frac{2 E_{1}}{N_{0}}, \frac{2 E_{2}}{N_{0}}$
Let, $I P = I$
$E A = E$

$X (g) \to X^{+} (g) + e^{-}$

$\frac{N_{0}}{2} I = E_{1}$

$I = \frac{2 E_{1}}{N_{0}}$

$X (g) + e^{-} \to X^{-} (g)$

$\frac{N_{o} E}{2} = E_{2}$

$E = \frac{2 E_{2}}{N_{o}}$