Question

The sum of three consecutive multiples of 3 is 63. Find all the numbers.

Answer 1

Let the first multiple of 3 be 3x.
The second and third multipes of 3 will be: 3x + 3 and 3x + 6
ATQ,
3x + (3x + 3) + (3x + 6) = 93
$\Rightarrow$ 9x + 9 = 63
$\Rightarrow$ 9x + 9 - 9 = 63 - 9
$\Rightarrow$ 9x = 54
$\Rightarrow$ x = 6

Therefore the numbers are:
3 $\times$ x = 3 $\times$ 6 = 18
​​​​​​​(3 $\times$ x) + 3 = ​​​​​​​3 $\times$ 6 + 3 = 21
​​​​​​​(3 $\times$ x) + 6 = ​​​​​​​3 $\times$ 6 + 6 = 24