Potassium chlorate is prepared by electrolysis of $K C l$ in basic solution as shown by following equation.

$6 O H^{-} + C l^{-} ⟶ C l O_{3}^{-} + 3 H_{2} O + 6 e^{-}$

A current of $x A$ has to be passed for 10 h to produce 10.0 g of potassoum chlorate. The value of $x$ is ____(Nearest integer)

(Molar mass of $K C l O_{3} = 122.6 g {mol}^{- 1}, F = 96500 C$ )

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1.00

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1.0

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Solution

Mass of $K C l O_{3} = 10 g$
$W = \frac{E}{F} \times I \times t$
$10 = \frac{122.6}{6 \times 96500} \times x \times 10 \times 3600$

$\Rightarrow x = 1.311 \approx 1$ (nearest integer)

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