Question

A list of species having the formula $X{Z}_4$ is given below $Xe{F}_4$, $S{F}_4$, $Si{F}_4$, $B{F}_4^{-}$, $Br{F}_4^{-}$, $\left[Cu\right(N{H}_3{)}_4]$, $[FeC{l}_4{]}^{2-}$, $[CoC{l}_4{]}^{2-}$ and
$[PtC{l}_4{]}^{2-}$.
Defining shape on the basis of the location of $X$ and $Z$ atoms, the total number of species having a square planar shape is:

• A. $4$
• B. $3$
• C. $2$
• D. $1$

Answer 1

The correct option is A $4$

Among the given molecules, $Xe{F}_4$, $Br{F}_4^{-}$, $\left[Cu\right(N{H}_3{)}_4{]}^2+$ and $[PtC{l}_4{]}^{2-}$ are square planar molecules.
Below are their structures:

The $S{F}_4$ molecule has a see-saw shape:

While the molecules like $Si{F}_4,B{F}_4^{-},\left[FeC{l}_4{]}^{2-}and\right[CoC{l}_4{]}^{2-}$ have tetrahedral shape.