Question

$N{H}_{4}Cl$ crystallises in a body-centered cubic lattice with an unit cell edge length of 387 pm. The distance between the oppositely charged ions in the lattice is:

• A. $335.15pm$
• B. $83.77pm$
• C. $274.46pm$
• D. $137.23pm$

Answer 1

The correct option is A $335.15pm$

In a BCC lattice, the distance between two oppositely charged ions $=\frac{\sqrt{3}}{2}a$ ,(where a = edge length of unit cell)
$=\frac{\sqrt{3}}{2}\times 387=335.15pm$