Question

Nishant goes to school at the speed of 3km/h and returns home at 4 km/h. Calculate the average speed and average velocity of Nishant's entire journey. Also, calculate the time taken for his total trip if his distance is 12km more than the displacement.

Answer 1

Dear student,

​​​​​​As initial and final position is same so displacement is zero.
As displacement is zero,
$averagevelocity=\frac{displacement}{time}=0$

$$\begin{gathered} Given, \\ dis\tan ceis12kmmorethandisplacement,anddsplacementiszero \\ so, \\ dis\tan ce=12km, \\ Dis\tan cefromhometoschool=\frac{12}{2}=6km \\ Timetakentogotoschool=\frac{dis\tan ce}{speed}=\frac{6}{3}=2hr \\ Timetakentogohome=\frac{dis\tan ce}{speed}=\frac{6}{4}=1.5hr \\ Totaltime=2+1.5=3.5hr \\ Averagespeed=\frac{totaldis\tan ce}{totaltime}=\frac{12}{3.5}=3.43km/h \end{gathered}$$

Regards,