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Valency and Oxidation State

Nitrogen form...

Question

Nitrogen forms five different compounds with oxygen. Match appropriate formulae for these compounds if the oxidation state of $N$ in them is $+ 1, + 2, + 3, + 4$ and $+ 5$ .

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Solution

Compound Oxidation state of N
$N_{2} O$ +1
$N O$ +2
$H {N O}_{2}$ +3
${N O}_{2}$ +4
$H {N O}_{3}$ +5

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Q. List-I has compounds and list-II has oxidation state of

S

in these compounds. The correct match is:

List-I	List-ll
A $) H_{2} S O_{4}$	1 $) + 4$
B $) H_{2} S_{2} O_{6}$	2 $) + 3$
C $) H_{2} S O_{3}$	3 $) + 2$
D $) H_{2} S_{2} O_{4}$	4 $) + 6$
	5 $) + 5$

Q. Match List-I (Compounds) with List-II (Oxidation states of Nitrogen) and select answer using the codes given below the lists.

	List - I		List - II
$(a)$	$N a N_{3}$	$(1)$	$+ 5$
$(b)$	$N_{2} H_{2}$	$(2)$	$+ 2$
$(c)$	$N O$	$(3)$	$- \frac{1}{3}$
$(d)$	$N_{2} O_{5}$	$(4)$	$- 1$

Select the correct statements among the following.

I)

V_{2} O_{5}

C r_{2} O_{3}

are amphoteric oxides.

I I)

Interstitial compounds of transition elements have an exact formulae.

I I I)

In its higher oxidation states, manganese forms stable compounds with oxygen and fluorine.

Q. Match list-I (compounds) with list-II (oxidation states of nitrogen).

Q. Match List-I (Compounds) with List-II (Oxidation states of nitrogen) and select answer using the codes given below the lists.

	List -I		List-II
$(a)$	$N a N_{3}$	$(1)$	$+ 5$
$(b)$	$N_{2} H_{2}$	$(2)$	$+ 2$
$(c)$	$N O$	$(3)$	$- \frac{1}{3}$
$(d)$	$N_{2} O_{5}$	$(4)$	$- 1$

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