You visited us 1 times! Enjoying our articles? Unlock Full Access!

Limiting Reagent or Reactant

Normality of ...

Question

Normality of solution obtained by mixing 10 mL of 1 N $H C I$ , 20 mL of 2 N $H_{2} S O_{4}$ and mL of 3 N $H N O_{3}$ is:

1.11 N

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2.22 N

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2.33 N

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

3.33 N

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A 2.33 N
$10 m l$ $(V_{1})$ of $1 N (S_{1}) H C l, 20 m l (V_{2})$ of $2 N (S_{2}) H_{2} {S O}_{4}$ and $30 m l (V_{3})$ of $3 N (S_{3})$ ${H N O}_{3}$ are mixed.
$∴$ Normality of mixing solution will be
$= \frac{V_{1} S_{1} + V_{2} S_{2} + V_{3} S_{3}}{V_{1} + V_{2} + V_{3}}$
$= \frac{10 \times 1 + 20 \times 2 + 30 \times 3}{10 + 20 + 30}$
$= 2.33 N$
$∴$ Correct answer is C.

Suggest Corrections

Similar questions

5 ml of N HCl, 20 ml of $N / 2 H_{2} S O_{4}$ and 30 ml of $N / 3 H N O_{3}$ are mixed together and volume made to one litre. The normality of the resulting solution is

Q. What will be the normality of a solution obtained by mixing

100 m L 0.1 N H C l

and

200 m L 0.25 N H N O_{3}

5

ml of

1 N

HCl,

20

ml of

\frac{N}{2}

H_{2} S O_{4}

and

30

ml of

\frac{N}{3}

H N O_{3}

are mixed together and the volume is made to

1

L. The normality of the resulting solution is :

Q. The normality of solution obtained by mixing

10 m l

N / 5 H C l

and

30 m l

N / 10 H C l

is:

Q. 50 ml of 0.2 N

H C l

, 50 ml of 0.1 N

H_{2} {S O}_{4}

and 100 ml of 0.2 N

{H N O}_{3}

are mixed. Normality of the resulting solution is:

Join BYJU'S Learning Program

Normality of solution obtained by mixing 10 mL of 1 N HCI, 20 mL of 2 N H2SO4 and mL of 3 N HNO3 is:

The correct option is A 2.33 N10ml (V1) of 1N(S1)HCl,20ml(V2) of 2N(S2)H2SO4 and 30ml(V3) of 3N(S3) HNO3 are mixed.∴ Normality of mixing solution will be=V1S1+V2S2+V3S3V1+V2+V3=10×1+20×2+30×310+20+30=2.33N∴ Correct answer is C.

Normality of solution obtained by mixing 10 mL of 1 N $H C I$ , 20 mL of 2 N $H_{2} S O_{4}$ and mL of 3 N $H N O_{3}$ is: