Number of geometrical isomers of $[P t (N H_{3}) (N O_{2}) P y (N H_{2} O H)]^{+}$ is :

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B 3
Here central atom Pt is connected with four different groups so it will have 3 different position isomers.(similar to attached picture)

Suggest Corrections

Similar questions

[P t (N H_{3}) (N O_{2}) P y (N H_{2} O H)]^{+}

[C o {(N H_{3})}_{3} {(N O_{3})}_{3}]

C H_{3} C H = N - O H

[C o (N O_{2})_{3} (N H_{3})_{3}]

[C o {(N H_{3})}_{3} {(N O_{2})}_{3}]

Join BYJU'S Learning Program