$[P t (N H_{3}) (N O_{2}) P y (N H_{2} O H)]^{+}$ will form geometrical isomers:

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Solution

The correct option is A 3
${[P t (C l) (P y) (N H_{3}) (N H_{2} O H)]}_{3}^{+}$ is square planer.
The structure are formed by fixing a group and then arranging all the groups.
Here, 4 different ligands are available.
So, 3 geometrical isomers shown by complex.

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