The number of geometrical isomers from $[C o {(N H_{3})}_{3} {(N O_{2})}_{3}]$ is:

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B 2
For octahedral $M a_{3} b_{3}$ complexes there are two isomers facial where the 'a' ligands occupy one face (all cis) and meridional where one of the 'a' ligands is moved so it is in the same equatorial plane as the other two 'a' ligands.

Suggest Corrections

Similar questions

c i s - [C o C l_{2} (e n)_{2}]

f a c i a l - [C o (N H_{3})_{3} (N O_{2})_{3}]

{[C o {({N H}_{3})}_{4} {({N O}_{2})}_{2}]}_{4}^{+}

C_{2}

[C o {(N H_{3})}_{3} {(N O_{3})}_{3}]

[P t (N H_{3}) (N O_{2}) P y (N H_{2} O H)]^{+}

Join BYJU'S Learning Program