Number of gram atoms of oxygen present in $0.3 m o l e$ of $(C O O H)_{2} .2 H_{2} O$ is

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0.9

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1.8

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Solution

The correct option is D
1.8

No. of gram atoms = no. of moles $\times$ $6$ (number of oxygen atoms)

= $0.3 \times 6$ = $1.8$

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Similar questions

Number of gram atoms of oxygen present in $0.3 m o l e$ of $(C O O H)_{2} .2 H_{2} O$ is

(C O O H)_{2} .2 H_{2} O

N_{2} O_{5}

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Calculate the number of
(a) Oxygen atoms in 0.10 mole of $N a_{2} C O_{3}$ . $10 H_{2} O$
(b) gram atoms in 4.6 gram of sodium.

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