For checking the bond order and paramagnetism
we have to write the electronic configuration
1.H−2 (Total electrons=3)
Configuration...σ1s2,σ∗1s1
It is paramagnetic due to the presence of unpair electrons
Bond order=2−12=0.5
2.C+2 (Total electrons=11)
Configuration:- σ1s2,σ∗1s2,σ2s2,σ∗2s2,π2p2xπ2p2y
Bond order=7−42=1.5
It is paramagnetic due to the presence of unpaired electrons
3.F+2 (Total electrons=17)
Configuration:-σ1s2,σ∗1s2,σ2s2,σ∗2s2,σ2p2z,(π2p2xπ2p2y),(π∗2p2xπ∗2p1y)
Bond order=10−72=1.5
It is paramagnetic due to the presence of unpaired electrons
∴ Among the given species 2 have a bond order=1.5 and are paramagnetic.