Question

$O_2$ gas at STP contained in a flask was replaced by $S{O}_2$ under same conditions. The weight of $S{O}_2$ will be:

• A. Equal to that of $O_2$
• B. Half that of $O_2$
• C. Twice that of $O_2$
• D. One-fourth of $O_2$

Answer 1

The correct option is C Twice that of $O_2$

1 mole of $O_2$ = 1 mole of $S{O}_2$
$32\text{g of}{O}_2=64\text{g of}S{O}_2$