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Mole Concept

O2 gas at STP...

Question

$O_{2}$ gas at STP contained in a flask was replaced by $S O_{2}$ under same conditions. The weight of $S O_{2}$ will be:

Equal to that of

O_{2}

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Half that of

O_{2}

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Twice that of

O_{2}

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One-fourth of

O_{2}

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Solution

The correct option is C Twice that of $O_{2}$
1 mole of $O_{2}$ = 1 mole of $S O_{2}$
$32 g of O_{2} = 64 g of S O_{2}$

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32

64

O_{2}

15^{0} C

750 m m

N

S O_{2}

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