Question

Obtain the zeros of $p\left(x\right)=x^2+9x+14$. Verify the relationship between the zeros and the coefficient of it.

Answer 1

obtain zeros P(x)$=x^2+9x+14$

$\to$ for zeros find P(x) = 0

$x^2+9x+14=0$

$x^2+7x+2x+14=0$

$x(x+7)+2(x+7)=0$

$(x+7)(x+2)=0$

$x=-7$ or $x=-2$

zeros is -7 & -2

$\to P(-7)=(-7{)}^2+9(-7)+14$

$=+49-63+14$

$=0$

$\to P(-2)=(-2{)}^2+9(-2)+14$

$=4-18+14$

$=0$