On analysis, a certain compound was found to contain iodine and oxygen in the ratio of 254 gm of iodine and 80gm of oxygen. The atomic mass of iodine is 127 and that of oxygen is 16. Which of the following is the formula of the compound

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I₂O

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I₅O₂

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I₂O₅

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Solution

The correct option is D I₂O₅
No of moles of iodine atoms = $\frac{254}{127} = 2$
No of moles of oxygen atoms = $\frac{80}{16} = 5$
Therefore the formula is $I_{2} O_{5}$

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On analysis, a certain compound was found to contain iodine and oxygen in the ratio of 254 gm of iodine and 80gm of oxygen. The atomic mass of iodine is 127 and that of oxygen is 16. Which of the following is the formula of the compound

The correct option is D I2O5No of moles of iodine atoms = 254127=2 No of moles of oxygen atoms = 8016=5 Therefore the formula is I2O5

The correct option is D I₂O₅
No of moles of iodine atoms = $\frac{254}{127} = 2$
No of moles of oxygen atoms = $\frac{80}{16} = 5$
Therefore the formula is $I_{2} O_{5}$