On analysis, a certain compound was found to contain iodine and oxygen in the ratio 254 g of iodine and 80 g of oxygen. The atomic mass of iodine is 127 and that of oxygen is 16. Which is the formula of the compound?

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I_{2} O

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I_{5} O_{2}

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I_{2} O_{5}

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Solution

The correct option is D $I_{2} O_{5}$
Number of moles of iodine atoms $= 254 / 127 = 2$
Number of moles of oxygen atoms $= 80 / 16 = 5$
Therefore formula of the compound is $I_{2} O_{5}$

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On analysis, a certain compound was found to contain iodine and oxygen in the ratio 254 g of iodine and 80 g of oxygen. The atomic mass of iodine is 127 and that of oxygen is 16. Which is the formula of the compound?

The correct option is D I2O5Number of moles of iodine atoms =254/127=2Number of moles of oxygen atoms =80/16=5Therefore formula of the compound is I2O5

The correct option is D $I_{2} O_{5}$
Number of moles of iodine atoms $= 254 / 127 = 2$
Number of moles of oxygen atoms $= 80 / 16 = 5$
Therefore formula of the compound is $I_{2} O_{5}$