On dividing $x (3 x^{2} - 27)$ by $3 (x - 3),$ we get .

x^{2} + 3 x

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x^{2} - 3 x

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x^{2} + 3 x^{2}

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x^{2} - 3 x^{2}

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Solution

The correct option is A $x^{2} + 3 x$
The given expression is
$x (3 x^{2} - 27)$

Taking 3 common we get
$= 3 x (x^{2} - 9)$

[Using $a^{2} - b^{2} = (a + b) (a - b)$ ]

= $3 x (x + 3) (x - 3)$

On dividing this expression with $3 (x - 3)$ we get,

$= \frac{3 x (x + 3) (x - 3)}{3 (x - 3)}$
$= x (x + 3)$
$= x^{2} + 3 x$

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Similar questions

Dividing $x (3 x^{2} - 27)$ by $3 (x - 3)$ gives $x^{2} + 3 x$ .

Divide $x (3 x^{2} - 27)$ by $3 (x - 3)$

State whether the statement is true or false.
Dividing $x (3 x^{2} - 27)$ by $3 (x - 3)$ gives $x^{2} + 3 x$ .

(5 x^{4} + 7 x^{3} + 2 x^{2} - 3 x + 5)

(x + 3)

Dividing $27$ by $4$ , we get .

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