One gm equivalent of a substance is present in:

0.25 m o l e

O_{2}

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0.5 m o l e

O_{2}

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1.00 m o l e

O_{2}

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8.00 m o l e

O_{2}

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Solution

The correct option is A $0.25 m o l e$ of $O_{2}$
Generally, $E = \frac{A t o m i c W e i g h t}{V a l e n c y} = \frac{A}{x}$ , where $E$ is equivalent weight

One $g$ equivalent is defined as the mass of an element / compound / ion which displaces $1 g m$ Hydrogen, $8 g$ Oxygen or $35.5 g$ of Chlorine.

So, $0.25 m o l e$ of $O_{2}$ gives $1 g$ equivalent.

$0.25 \times 32 = 8 g$ of $O_{2}$

Hence, option $A$ is correct.

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Question 20

Which of the following options represents the correct bond order?

(a) $O_{2}^{-} > O_{2} > O_{2}^{+}$

(b) $O_{2}^{-} < O_{2} < O_{2}^{+}$

(d) $O_{2}^{-} < O_{2} > O_{2}^{+}$

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