One litre of a gas weighs 4g at 300 K and 1 atm. If the pressure is reduced to 0.75 atm, the temperature at which one litre of the same gas weights 2g is

600 K

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900 K

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450 K

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800 K

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Solution

The correct option is C
450 K

$\frac{P_{1} V_{1}}{P_{2} V_{2}}$ = $\frac{W_{1}}{W_{2}}$ $\frac{T_{1}}{T_{2}}$

$\frac{1 \times 1}{0.75 \times 1}$ = $\frac{4}{2}$ $\frac{300}{T_{2}}$

$T_{2}$ = 450K

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Similar questions

One litre of a gas weights 2g at 300 K and 1 atm. pressure. If the pressure is made 0.75 atm, at which temperature will one litre of the same gas weigh 1g

Q. One litre of a gas weighs

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at which of the following temperatures will one litre of the same gas, weigh one gram?

Q. One liter of a gas weight

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Q. 1litre of a gas weights 2g at 300K and 1atm pressure.If the pressure is made 0.75atm at which temperature will 1L of same gas weighs 1g ?

Q. One litre of a gas weighs 2g at

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and

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atm. If the pressure is made

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atm at what temperature will one litre of the same gas weigh one gram?

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One litre of a gas weighs 4g at 300 K and 1 atm. If the pressure is reduced to 0.75 atm, the temperature at which one litre of the same gas weights 2g is

The correct option is C 450 K P1V1P2V2 = W1W2 T1T2 1×10.75×1 = 42300T2 T2 = 450K

The correct option is C
450 K

$\frac{P_{1} V_{1}}{P_{2} V_{2}}$ = $\frac{W_{1}}{W_{2}}$ $\frac{T_{1}}{T_{2}}$

$\frac{1 \times 1}{0.75 \times 1}$ = $\frac{4}{2}$ $\frac{300}{T_{2}}$

$T_{2}$ = 450K