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Limiting Reagent or Reactant

One mole Ba...

Question

One mole $B a F_{2}$ is treated with two moles of $H_{2} S O_{4}$ .To make the resulting mixture neutral, $N a O H$ is added. Moles of $N a O H$ required in this process is :

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Solution

$B a F_{2} 1 m o l + H_{2} S O_{4} 1 m o l ⟶ B a S O_{4} 1 m o l + H_{2} F_{2} 1 m o l$
Thus, unreacted $H_{2} S O_{4} = 1$ mol
$H_{2} F_{2}$ formed $= 1$ mol

$H_{2} S O_{4} 1 m o l + 2 N a O H 2 m o l ⟶ N a_{2} S O_{4} + 2 H_{2} O$

$H_{2} F_{2} 1 m o l + 2 N a O H 2 m o l ⟶ N a_{2} F_{2} + 2 H_{2} O$

Thus, total $N a O H$ required by $1$ mol $H_{2} F_{2}$ (formed) and $1$ mol $H_{2} S O_{4}$ (unreacted) $= 4$ mol.

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