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Question

One mole BaF2 is treated with two moles of H2SO4. To make the resulting mixture neutral, NaOH is added. NaOH required in this process is (in moles):

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Solution

BaF21mol+H2SO41molBaSO41mol+2HF2mol

Given: 1 mol 2 mol
Thus, unreacted H2SO4=1 mol
HF formed =2 mol
H2SO41mol+2NaOH2molNa2SO4+2H2O
2HF2mol+2NaOH2mol2NaF+2H2O

Thus, total NaOH required by =4 mol

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