One mole of fluorine is reacted with two moles of hot and concentrated KOH. The products formed are KF,H2O and O2 The molar ratio of KF,H2O and O2, respectively is;
A
1:1:2
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B
2:1:0.5
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C
1:2:1
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D
2:1:2
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Solution
The correct option is B2:1:0.5 The chemical reaction is 2F2+4KOH→4KF+O2+2H2O
Therefore, for 1mole of F2 the molar ratio will be 2:1:0.5