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Standard XII

Chemistry

Types of Redox Reactions

One mole of N...

Question

One mole of $N_{2} H_{4}$ loses 10 mol of electrons to form a new compound Y. Assuming that all nitrogen appear in the new compound, what is the oxidation state of $N_{2}$ in Y ? (There is no change in the oxidation state of hydrogen)

+ 3

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Solution

The correct option is A
+ 3

$N_{2}^{a +}$ $⟶$ $N_{2}^{a +}$ + $10^{e -}$

$∴$ 2a-[2 $\times$ (-2)] =10

$∴$ a =+3

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Similar questions

A mole of $N_{2} H_{4}$ loses 10 mol of electrons to form a new compound Y. Assuming that all the nitrogen appears in the new compound, what is the oxidation state of nitrogen in Y? (There is no change in the oxidation number of hydrogen.)

Q. A mole of

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loses 10 mol of electrons to form a new compound Y. Assuming that all the nitrogen appears in the new compound, what is the oxidation state of nitrogen in Y ? ( There is no change in the oxidation number of hydrogen. )

1

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One mole ofN2H4 loses 10 mol of electrons to form a new compound Y. Assuming that all nitrogen appear in the new compound, what is the oxidation state ofN2 in Y ? (There is no change in the oxidation state of hydrogen)

The correct option is A + 3 Na+2⟶Na+2 +10e− ∴2a-[2×(-2)] =10 ∴ a =+3

One mole of $N_{2} H_{4}$ loses 10 mol of electrons to form a new compound Y. Assuming that all nitrogen appear in the new compound, what is the oxidation state of $N_{2}$ in Y ? (There is no change in the oxidation state of hydrogen)

The correct option is A
+ 3

$N_{2}^{a +}$ $⟶$ $N_{2}^{a +}$ + $10^{e -}$

$∴$ 2a-[2 $\times$ (-2)] =10

$∴$ a =+3