Question

One mole of$N_2{H}_4$ loses 10 mol of electrons to form a new compound Y. Assuming that all nitrogen appears in the new compound, what is the oxidation state of$N_2$ in Y ? (There is no change in the oxidation state of hydrogen)

• A. + 3
• B. - 3
• C. - 1
• D. + 5

Answer 1

The correct option is A

+ 3

$N_2^{a+}$$⟶$$N_2^{a+}$ +${10}^{e-}$

$\therefore$2a-[2$\times$(-2)] =10

$\therefore$ a =+3