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Stoichiometric Calculations

One mole of ...

Question

One mole of $S O_{2} C l_{2}$ is dissolved in water and $C a (O H)_{2}$ is added to neutralise acidic solution. Moles of $C a (O H)_{2}$ required are :

A

2

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B

3

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C

4

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D

5

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Solution

The correct option is C $2$
The reactions are as follows:
$S O_{2} C l_{2} 1 m o l + 2 H_{2} O ⟶ H_{2} S O_{4} 1 m o l + 2 H C l 2 m o l$
$H_{2} S O_{4} + C a (O H)_{2} ⟶ C a S O_{4} + 2 H_{2} O$
$2 H C l + C a (O H)_{2} ⟶ C a C l_{2} + 2 H_{2} O$
Thus, total $C a (O H)_{2}$ required $= 2$ mol.

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