wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

One mole of soda ash dissolves in water with evolution of 25 kJ of heat. Dissociation of 1 mol of the hydrate crystals in water resulted in the absorption of 67 kJ of heat. The heat released due to hydration of soda ash is

A
92 kJ
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
+42 kJ
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
42 kJ
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
102 kJ
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 92 kJ
From Hess's law, We know
Hsoln(anhydrous salt)=Hhydr. + Hsoln(Hydrated salt)

Hhydr.=Hsoln(anhydrous salt) Hsoln(Hydrated salt)
Given,
Hsoln(Hydrated salt)=25 kJHsoln(anhydrous salt) =+67 kJHhydr.=To be calculated
Putting all values in the formula, we get;
Hhydr.=25(+67)
Hhydr.=92 kJ

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Thermochemistry
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon