One of the following amide will not undergo Hoffmann bromamide reaction:

$C H_{3} C O N H_{2}$

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$C H_{3} C O N H C H_{3}$

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$C_{6} H_{5} C O N H_{2}$

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$C H_{3} C H_{2} C O N H_{2}$

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Solution

The correct option is B
$C H_{3} C O N H C H_{3}$

$C H_{3} C O N H C H_{3}$ is an example for secondary amide. Hoffmann bromamide reaction is answered by primary amide.

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We can obtain ethylamine by Hoffmann bromamide reaction. The amide used in this reaction is:

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