$1 H C \equiv 2 C 3 C H = 4 C H 5 C H_{3}$

Which carbon atom will show minimum electronegativity?

Fifth

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Third

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First

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Second

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Solution

The correct option is A Fifth
$1 H C \equiv 2 C 3 C H = 4 C H 5 C H_{3}$

Fifth carbon atom will show minimum electronegativity.

Electronegativity of carbon in organic compounds depends upon the state of hybridization in the concerned compound. It is highest in sp state and lowest in $s p^{3}$ state.

$s p > s p^{2} > s p^{3}$

Hence, the correct option is $A$

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Similar questions

Which carbon atom will show minimum electronegativity -

H $^{1} C$ $\equiv$ $^{2} C$ - C $^{3} H$ - C $^{4} H$ - C $^{5} H$

C_{1}

C_{3}

C H_{3} - C H = C H - C H_{3}

C 1 H_{3} - C 2 H = C 3 = C 4 H_{2}

1^{\circ}, 2^{\circ} a n d 3^{\circ}

C H_{3} - C H | O H - C H | C H_{3} - C H_{2} - C H_{3}

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