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Question

Oxidation number of each chlorine in CaOCl2 is 1.
If true enter 1, else enter 0.
  1. 0

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Solution

The correct option is A 0
Let x be the oxidation number of Cl in CaOCl2.
Since the overall
charge on the complex is 0, the sum of oxidation states of all elements in
it should be equal to 0.
Therefore, +2+2+2(x)=0
or, x=0
Thus, the oxidation number of Cl in CaOCl2 is 0.

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