Oxidation number of each chlorine in CaOCl2 is −1. If true enter 1, else enter 0.
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Solution
The correct option is A 0 Let x be the oxidation number of Cl in CaOCl2. Since the overall charge on the complex is 0, the sum of oxidation states of all elements in it should be equal to 0. Therefore, +2+−2+2(x)=0 or, x=0 Thus, the oxidation number of Cl in CaOCl2 is 0.