Oxidation number of Mn in MnO3Cl is +6. If true enter 1, else enter 0.
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Solution
The correct option is A 0 Let x be the oxidation number of Mn in MnO3Cl. Since the overall charge on the complex is 0, the sum of oxidation states of all elements in it should be equal to 0. Therefore, x+3(−2)+(−1)=0 or, x=7.