Oxidation number of $M n$ in $M n O_{4}^{-}$ is +4.

True

No worries! We‘ve got your back. Try BYJU‘S free classes today!

False

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is B False
Solution
Charge on $M n O_{4}^{- 1}$ = Oxidation no.(Mn)+ 4* Oxidation no.(O)
-1=x+4*(-2)
x=+7
The correct option is B

Suggest Corrections

Similar questions

In MnO₄^-4 the oxidation number of Mn is-

M n

[M n O_{4}]^{-}

M n

M n S O_{4}

M n C_{2} O_{4}

M n

M n_{3} O_{4}

M n O_{4}^{- 2}

M n

M n O_{2}, M n O_{4}^{2 -}, M n O_{4}^{-}

4

+ 6

+ 7

K_{2} M n O_{4}

Join BYJU'S Learning Program