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Electronic Configuration and Oxidation States

Oxidation num...

Question

Oxidation number of sulphur in $H_{2} {S O}_{5}$ is $+ 6$ . If true enter 1 else 0.

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Solution

$H_{2} {S O}_{5} + H_{2} O ⟶ {2 H}_{2} {S O}_{4} + H_{2} O_{2}$
$H_{2} S O_{5}$ consists of peroxide linkage. Each oxygen atom in peroxide has oxidation number of $- 1$ .
Hence, the oxidation state of $H_{2} S O_{5}$ is $+ 6$ .

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