1.Define P.E? write its relation and SI unit.
2.How much % variation in K.E seen when the momentum of a body is doubled?
3.derive the relation for potential energy.
4.How much work done by our earth in going around the sun once? Give reason.
5.The height of qutbminar is 75m.How much work done when a 50kg man reach the top?
6.factors affecting the escape velocity.
7.graphically show the variation of P.E and K.E of a freely falling body

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Solution

The relation between kinetic energy and momentum is
E = p²/2m
so, in the first case,
E1 = (p1)²/2m
if the momentum is doubled then p2 = 2p1
Then,
E2 = (2p1)²/2m = 4[(p1)²/2m] = 4E1
thus,
the kinetic energy increases by (E2/E1) x 100 = 400%

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The relation between kinetic energy and momentum isE = p2/2mso, in the first case,E1 = (p1)2/2mif the momentum is doubled then p2 = 2p1Then,E2 = (2p1)2/2m = 4[(p1)2/2m] = 4E1thus,the kinetic energy increases by (E2/E1) x 100 = 400%

The relation between kinetic energy and momentum is
E = p²/2m
so, in the first case,
E1 = (p1)²/2m
if the momentum is doubled then p2 = 2p1
Then,
E2 = (2p1)²/2m = 4[(p1)²/2m] = 4E1
thus,
the kinetic energy increases by (E2/E1) x 100 = 400%