Question

29. The brakes applied to a car produce an acceleration of 6 m/s2 in the opposite direction to

the motion. If the car takes two seconds to stop after the application of brakes, calculate the distance, it

travels during this time.

Answer 1

we shall use the following equation

v = u + at

here

v = 0

a = -6 m/s2

and t = 2 secs

so,

u = -at = -(-6)x2

or

u = 12 m/s

and also

s = ut + (1/2)at²

here,

u = 12 m/s

a = 6 m/s²

t = 2 secs

so,

s = 12x2 + (1/2)x(6)(2)²

or

s = 24 + 3x4

thus, the distance travelled by the car will be

s = 36 m