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Question

A bomb at rest explodes into two fragments of masses 3.0 kg and 1.0 kg. The total kinetic energy of the fragment is 6x10^4 joules. Calculate the kinetic energy of the bigger fragment. Also, in which type of collision, elastic or inelastic, momentum is conserved?

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Solution

m1 = 3 kgm2 = 1 kg So by conservation of momentum:m1v1 +m2v2 = (m1+m2)0 m1v1 +m2v2 = 0 m1v1 =-m2v23v1 =-1v2-3v1 =v2Total kinetic energy :1/2* m1v12+1/2* m2v22 =6 *1041/2( 3*v12+v22) = 6 *1043*v12+(-3v1)2= 12 *1043*v12+9v12= 12 *10412v12= 12 *104v12= 104v1= 100 m/sso v2= -300 m/s
In elastic collision the momentum is conserved as there is no loss in the body deterioration!

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