a constant force of 12N acts on a body for 4s . find the change in the linear momentum of the body.

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Solution

In case of constant force,
$Change in the linear momentum = F \times ∆ t = 12 \times 4 = 48 N - s$

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a constant force of 12N acts on a body for 4s . find the change in the linear momentum of the body.

In case of constant force, Change in the linear momentum=F×∆t=12×4=48 N-s

In case of constant force,
$Change in the linear momentum = F \times ∆ t = 12 \times 4 = 48 N - s$