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a man spends ...

Question

a man spends 1/2 of his money in one shop,2/3 of the remainder in another shop and 4/5 of what is left he gives away.If he has RS 10 left,how much did he have at first.

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Solution

let he had Rs . x initially
spent on 1 shop = Rs.
remaining = x-x/2
= Rs.
Spent on 2^nd shop =
= Rs.
Remaining =
=
=
= Rs.
Now he gave = Rs.
= Rs.
Remaining =
=
=
Hence , = 10
x = Rs. 300
hence , initially he had Rs.300

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