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Question

a person is throwing balls into the air one after other . he throws the second ball when first ball is at the heighest point . if he is throwing two balls every second ,how high do they rise

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Solution

When person throws two balls in every second then first ball reaches to the highest point in 1 s.at the highest point velocity is zero(v=0).v = u + atacceleration = - gt = 1 s0 = u - gu = gwhere u is the initial velocity.Distnace travelled in one second is the maximum height covered by the ball.s = ut + 12at2s = g(1) - g2×1×1s = g2s = 9.8/2s = 4.9 m

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