A uniform wire of length 1m and radius 1mm is twisted by an angle 30degree. Find the shear strain (in degree) produced in it.

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Solution

Here, L = 1 m
r = 1 mm = 0.001 m
α = 30⁰

shear strain (θ) = $\frac{Δ L}{L}$ = $\frac{r α}{L} = \frac{0.001 X 30^{0}}{1} = 0 . 03^{0}$

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A uniform wire of length 1m and radius 1mm is twisted by an angle 30degree. Find the shear strain (in degree) produced in it.

Here, L = 1 m r = 1 mm = 0.001 m α​ = 300 shear strain (θ) = ΔLL = r αL =0.001 X 3001 =0.030

Here, L = 1 m
r = 1 mm = 0.001 m
α = 30⁰

shear strain (θ) = $\frac{Δ L}{L}$ = $\frac{r α}{L} = \frac{0.001 X 30^{0}}{1} = 0 . 03^{0}$