If (x-p) and (x-q) are the factors of the expression ax2+bx+c, then the values of a and b are:
1, -(p+q)
(x-p) and (x-q) are the factors of the expression ax2+bx+c,
⇒ ax2+bx+c=(x−p)(x−q)
⟹ax2+bx+c=x2−(p+q)x+pq
By comparing the co-efficients of x2, x and the constant term,we get,
a=1, b=−(p+q) and c=pq