‘p’ and ‘q’ are the zeroes of the polynomial
$a x^{2} + b x + c$ . The values of $a$ and $b$ are and respectively.

- 1

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1

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(p + q)

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- (p + q)

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Solution

The correct options are
B $1$
D $- (p + q)$
Since, ‘p’ and ‘q’ are the zeroes of the polynomial $a x^{2} + b x + c$ ,

$(x - p)$ and $(x - q)$ are the factors of the expression $a x^{2} + b x + c$ ,

so $a x^{2} + b x + c = (x - p) (x - q)$

$⟹ a x^{2} + b x + c = x^{2} - (p + q) x + p q$

By comparing the co-efficients of $x^{2}$ , $x$ , and the constant term, we get

$a = 1$ , $b = - (p + q)$ and $c = p q .$

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