Calculate the energy transfered by a 5 ampere current flowing through a resistors of 2 ohms for 30 minutes
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Solution
Given, I = 5 A
R = 2
t = 30 min = 1800 s
Heat energy produced by electric current in the resistor is given by :
H = I2 Rt
H = (5)2 X 2 X 1800 = 90,000 J = 90 kJ