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Question

The 5th term of an arithmetic sequence is 11 and its 12th term is 32. What are its first three terms?

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Solution

5th term of the arithmetic sequence = 11

12th term of the arithmetic sequence = 32

To get the 12th term from the 5th term, we must add the common difference seven times to the 5th term.

The number to be added is 32 − 11 = 21

Common difference = = 3

We can get the 5th term from the 1st term by adding the common difference four times to the 1st term.

So, in this sequence, the 5th term, i.e., 11 is received by adding 4 × 3 = 12 to the 1st term.

1st term = 11 − 12 = 1

Now, the 1st term is 1 and the common difference is 3.

2nd term = 1 + 3 = 2

3rd term = 2 + 3 = 5

So, the first three terms of the given arithmetic sequence are 1, 2 and 5.


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