give the algebraic expression for this:
twice the sum of a number and another number, which is three more than the first number

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Solution

twice the sum of a number and another number, which is three more than the first number
Let the first number be "x".
Then 3 more than x would be x+3.
So twice the sum of x and x+3 would be
2[ x+ (x+3)] = 2( 2x+3) = 4x+6

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give the algebraic expression for this:twice the sum of a number and another number, which is three more than the first number

twice the sum of a number and another number, which is three more than the first numberLet the first number be "x".Then 3 more than x would be x+3.So twice the sum of x and x+3 would be2[ x+ (x+3)] = 2( 2x+3) = 4x+6

give the algebraic expression for this:
twice the sum of a number and another number, which is three more than the first number

twice the sum of a number and another number, which is three more than the first number
Let the first number be "x".
Then 3 more than x would be x+3.
So twice the sum of x and x+3 would be
2[ x+ (x+3)] = 2( 2x+3) = 4x+6