If 10 volumes of dihydrogen react with 5 volumes of dioxygen gas, how many volumes of water will be produced?

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Solution

Reaction for the formation of water:
$H_{2} + \frac{1}{2} O_{2} \to H_{2} O$
1volume of dihydrogen gas reacts with 1/2 volume of dioxygen gas to form 1 volume of water.
So, ratio of volumes of dihydrogen and dioxygen gas is 1: 1/2 =2:1
ratio of dihydrogen and water produced = 1:1

Given ratio of dihydrogen and dioxygen gas = 10: 5 = 2:1
Therefore, volume of water produced = volume of dihydrogen gas = 10 volumes.

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