In a cricket match,a batsman hits boundary in 20% of the balls he played. Find the probability that he did not hit a boundary.

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Solution

He hits the boundary in 20% of balls

$P (h i t t i n g b o u n d a r y) = \frac{20}{100} = 0.2 P (n o t h i t t i n g b o u n d a r y) = 1 - 0.2 = 0.8 = 80 %$

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In a cricket match,a batsman hits boundary in 20% of the balls he played. Find the probability that he did not hit a boundary.

He hits the boundary in 20% of balls P(hitting boundary) = 20100 = 0.2P (not hitting boundary) = 1-0.2 = 0.8 = 80%

He hits the boundary in 20% of balls

$P (h i t t i n g b o u n d a r y) = \frac{20}{100} = 0.2 P (n o t h i t t i n g b o u n d a r y) = 1 - 0.2 = 0.8 = 80 %$