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Question
In a reaction, 10 g of calcium carbonate reacts with 7.3 g of hydrochloric acid. The products of reaction are 11.1 g of calcium chloride, 1.8 g of water and 4.4 g of carbon dioxide gas. Show that these observations are in agreement with the law of conservation of mass.
In a reaction, 10 g of calcium carbonate reacts with 7.3 g of hydrochloric acid. The products of reaction are 11.1 g of calcium chloride, 1.8 g of water and 4.4 g of carbon dioxide gas. Show that these observations are in agreement with the law of conservation of mass.
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Solution
The reaction is as follows:
CaCO3 + 2HCl → CaCl2 + H2O + CO2
10 g 7.3 g 11.1 g 1.8 g 4.4 g
The law of conservation of mass states that the mass of a closed system will remain constant in a chemical reaction. In other words, mass can neither be created nor destroyed in a chemical reaction. It means the mass of reactant will be equal to mass of product.
Total mass of reactant = 10 + 7.3 g
= 17.3 g
Total mass of product - 11.1 + 1.8 + 4.4
= 17.3 g
So, total mass of reactant will be equal to mass of product. Thus it follow the law of conservation of mass.
CaCO3 + 2HCl → CaCl2 + H2O + CO2
10 g 7.3 g 11.1 g 1.8 g 4.4 g
The law of conservation of mass states that the mass of a closed system will remain constant in a chemical reaction. In other words, mass can neither be created nor destroyed in a chemical reaction. It means the mass of reactant will be equal to mass of product.
Total mass of reactant = 10 + 7.3 g
= 17.3 g
Total mass of product - 11.1 + 1.8 + 4.4
= 17.3 g
So, total mass of reactant will be equal to mass of product. Thus it follow the law of conservation of mass.
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