In a reaction, 5.3 g of sodium carbonate reacted with 6 g of ethanoic acid. The products were 2.2 g of carbon dioxide, 0.9 g water and 8.2 g of sodium ethanoate. Show that these observations are in agreement with the law of conservation of mass.

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Solution

According to the question,

$N a_{2} C O_{3} + C H_{3} C O O H \to C O_{2} + H_{2} O + C H_{3} C O O N a$

Mass of reactants $= 5.3 + 6 = 11.3 g m$
Mass of products $= 2.2 + 0.9 + 8.2 = 11.3 g m$

This shows, that during a chemical reaction, the mass of reactant = mass of the product.

Hence, it shows the law of conservation of mass.

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In a reaction, 5.3 g of sodium carbonate reacted with 6 g of ethanoic acid. The products were 2.2 g of carbon dioxide, 0.9 g water and 8.2 g of sodium ethanoate. Show that these observations are in agreement with the law of conservation of mass.

Sodium carbonate + Ethanoic acid

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Sodium ethanoate + Carbon dioxide + Water

Q. In a reaction 5.3 gram of sodium carbonate reacted with 6 team of ethanoic acid the product were 2.2 gram of carbon dioxide, 0.9 gram of water and 8.2 gram of sodium ethanoate show that these observations are in agreement with the law of conservation of mass. sodium carbonate + ethanoic acid gives sodium ethanoate+ carbon dioxide + water

In a reaction, 5.3 g of sodium carbonate reacted with 6 g of acetic acid. The products were 2.2 g of carbon dioxide, 0.9 g of water and 8.2 g of sodium acetate. Show that these observations are in agreement with the law of conservation of mass.
Sodium Carbonate + Acetic Acid $\to$ Sodium Acetate + Carbon Dioxide + Water

Q. In a reaction

5.3 g

of sodium carbonate reacted with

6 g

of ethanoic acid. The products were

2.2 g

of carbondioxide,

0.9 g

of water and

8.2 g

of sodium ethanoate. These observations are in agreement with :

In a reaction, In a reaction, 5.3 g of sodium carbonate reacted with 6 g of ethanoic acid. The products were 2.2 g of carbon dioxide, 0.9 g water and 8.2 g of sodium ethanoate. Which law is applicable in this case?

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In a reaction, 5.3 g of sodium carbonate reacted with 6 g of ethanoic acid. The products were 2.2 g of carbon dioxide, 0.9 g water and 8.2 g of sodium ethanoate. Show that these observations are in agreement with the law of conservation of mass.

According to the question,Na2CO3+CH3COOH→CO2+H2O+CH3COONaMass of reactants =5.3+6=11.3 gmMass of products =2.2+0.9+8.2=11.3 gmThis shows, that during a chemical reaction, the mass of reactant = mass of the product.Hence, it shows the law of conservation of mass.